182 lines
4.8 KiB
C++
182 lines
4.8 KiB
C++
/*
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* Program to factor big numbers using Williams (p+1) method.
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* Works when for some prime divisor p of n, p+1 has only
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* small factors.
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* See "Speeding the Pollard and Elliptic Curve Methods"
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* by Peter Montgomery, Math. Comp. Vol. 48. Jan. 1987 pp243-264
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*
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* Requires: big.cpp zzn.cpp
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*
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*/
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#include <iostream>
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#include <iomanip>
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#include "zzn.h"
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using namespace std;
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#define LIMIT1 10000 /* must be int, and > MULT/2 */
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#define LIMIT2 500000L /* may be long */
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#define NEXT 13 /* next small prime */
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#define MULT 2310 /* must be int, product of small primes 2.3.. */
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#define NTRYS 3 /* number of attempts */
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Miracl precision=50; /* number of ints per ZZn */
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miracl *mip;
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static long p;
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static int iv;
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static ZZn b,q,fvw,fd,fp,fn,fu[1+MULT/2];
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static BOOL cp[1+MULT/2],Plus[1+MULT/2],Minus[1+MULT/2];
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void marks(long start)
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{ /* mark non-primes in this interval. Note *
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* that those < NEXT are dealt with already */
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int i,pr,j,k;
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for (j=1;j<=MULT/2;j+=2) Plus[j]=Minus[j]=TRUE;
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for (i=0;;i++)
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{ /* mark in both directions */
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pr=mip->PRIMES[i];
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if (pr<NEXT) continue;
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if ((long)pr*pr>start) break;
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k=pr-start%pr;
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for (j=k;j<=MULT/2;j+=pr)
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Plus[j]=FALSE;
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k=start%pr;
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for (j=k;j<=MULT/2;j+=pr)
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Minus[j]=FALSE;
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}
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}
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void next_phase()
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{ /* now change gear */
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ZZn t;
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long interval;
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fp=fu[1]=b;
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fd=b*b-2;
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fn=fd*b-b;
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for (int m=5;m<=MULT/2;m+=2)
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{ /* store fu[m] = Vm(b) */
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t=fn*fd-fp;
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fp=fn;
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fn=t;
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if (!cp[m]) continue;
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fu[m]=t;
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}
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fd=luc(b,MULT);
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iv=p/MULT;
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if (p%MULT>MULT/2) iv++;
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interval=(long)iv*MULT;
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p=interval+1;
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marks(interval);
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fvw=luc(fd,iv,&fp);
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q=fvw-fu[p%MULT];
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}
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int giant_step()
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{ /* increment giant step */
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long interval;
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ZZn t;
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iv++;
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interval=(long)iv*MULT;
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p=interval+1;
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marks(interval);
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t=fvw;
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fvw=fvw*fd-fp;
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fp=t;
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return 1;
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}
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int main()
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{ /* factoring program using Williams (p+1) method */
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int k,phase,m,nt,pos,btch;
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long i,pa;
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Big n,t;
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mip=&precision;
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gprime(LIMIT1);
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for (m=1;m<=MULT/2;m+=2)
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if (igcd(MULT,m)==1) cp[m]=TRUE;
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else cp[m]=FALSE;
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cout << "input number to be factored\n";
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cin >> n;
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if (prime(n))
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{
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cout << "this number is prime!\n";
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return 0;
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}
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modulo(n); /* do all arithmetic mod n */
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for (nt=0,k=3;k<10;k++)
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{ /* try more than once for p+1 condition (may be p-1) */
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b=k; /* try b=3,4,5.. */
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nt++;
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phase=1;
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p=0;
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btch=50;
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i=0;
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cout << "phase 1 - trying all primes less than " << LIMIT1;
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cout << "\nprime= " << setw(8) << p;
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forever
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{ /* main loop */
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if (phase==1)
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{ /* looking for all factors of p+1 < LIMIT1 */
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p=mip->PRIMES[i];
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if (mip->PRIMES[i+1]==0)
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{ /* now change gear */
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phase=2;
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cout << "\nphase 2 - trying last prime less than ";
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cout << LIMIT2 << "\nprime= " << setw(8) << p;
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next_phase();
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btch*=100;
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i++;
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continue;
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}
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pa=p;
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while ((LIMIT1/p) > pa) pa*=p;
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q=luc(b,(int)pa);
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b=q;
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q-=2;
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}
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else
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{ /* looking for last large prime factor of (p+1) */
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p+=2;
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pos=p%MULT;
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if (pos>MULT/2) pos=giant_step();
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if (!cp[pos]) continue;
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/* if neither interval+/-pos is prime, don't bother */
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if (!Plus[pos] && !Minus[pos]) continue;
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q*=(fvw-fu[pos]); /* batching gcds */
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}
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if (i++%btch==0)
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{ /* try for a solution */
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cout << "\b\b\b\b\b\b\b\b" << setw(8) << p << flush;
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t=gcd(q,n);
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if (t==1)
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{
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if (p>LIMIT2) break;
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else continue;
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}
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if (t==n)
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{
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cout << "\ndegenerate case";
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break;
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}
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if (prime(t)) cout << "\nprime factor " << t;
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else cout << "\ncomposite factor " << t;
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n/=t;
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if (prime(n)) cout << "\nprime factor " << n;
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else cout << "\ncomposite factor " << n;
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cout << endl;
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return 0;
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}
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}
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if (nt>=NTRYS) break;
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cout << "\ntrying again\n";
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}
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cout << "\nfailed to factor\n";
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return 0;
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}
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